Bearing capacity of inclined section
Objective: Determine the load-bearing capacity of an inclined section
Task: Check the shear resistance of an element with transverse reinforcement
References: Design of reinforced concrete structures. Guide / A.M. Bambura, I.R. Sazonova, O.V. Dorohova, O.V. Wojciechovsky; Under the editorship A.M. Bambura - Kyiv: Master of Books, 2018. - 240 p. (Example 5.2, p. 151-153)
Initial data file:
ARBAT mode – Strength of RC Section
Example-5.2-DBN.SAV
report – Arbat 5.2-DBN.doc
Compliance with the codes: DBN V 2.6-98:2009, DSTU B.V 2.6-156:2010
Initial data:
b×h = 300×600 мм |
Cross-section sizes |
а = 25 мм |
The size of the protective layer of concrete |
VEd = 91 кН |
Design shear force |
3∅25А500С |
Lower tension reinforcement |
Concrete class Класс поперечной арматуры |
С25/30 A400С |
Initial data in ARBAT:
Importance factor γn = 1
Importance factor (emergency state) 1
Member length 6 m
Effective length factor in the XoY plane 1
Effective length factor in the XoZ plane 1
Random eccentricity along Z according to DBN B.2.6-98:2009 with Change No 1
Random eccentricity along Y according to DBN B.2.6-98:2009 with Change No 1
Structure is statically determinate
Section
b = 300 mm h = 600 mm a1 = 25 mm a2 = 25 mm
|
S1 - 3∅25 Transverse reinforcement along axis Z 2∅8, spacing of transverce reinforcement 75 mm
|
---|
Reinforcement |
Class |
Additional service factor |
---|---|---|
Longitudinal |
A500C |
1 |
Transverse |
A400C |
1 |
Concrete
Concrete type: Heavy-weight
Concrete class: C25/30
Aggregate: Quartzite
Additional parameters |
||
---|---|---|
additional service factor |
1 |
|
Concrete age (days) |
28 |
|
Cement strength class |
Class R |
|
Creep progress time |
36500 |
days |
Temperature T(Δt) |
20 |
°C |
The number of days where a temperature T prevails Δt |
28 |
days |
Relative humidity |
40 |
% |
Results of analysis by load case combinations
|
N |
My |
Qz |
Mz |
Qy |
T |
Factor for sustained load |
Short-term |
Seismicity |
Special |
---|---|---|---|---|---|---|---|---|---|---|
kN |
T*m |
kN |
T*m |
kN |
T*m |
|||||
1 |
1 |
0 |
191 |
0 |
0 |
0 |
1 |
|
|
|
Checked according to DBN |
Check |
Utilization Factor |
---|---|---|
Sec. 6.2.1.7 |
Shear resistance to Vz without transverse reinforcement |
1,915 |
Sec. 6.2.1.6 |
Shear resistance to Vz with transverse reinforcement |
0,987 |
Comparison of solutions
Check |
Shear resistance without transverse reinforcement |
Guide |
191/100=1,91 |
ARBAT |
1,915 |
Deviation, % |
0,3 % |
Check |
Shear resistance with transverse reinforcement |
Guide |
191/194=0,985 |
ARBAT |
0,987 |
Deviation, % |
0,2 % |