Check of the Load-bearing Capacity of a Section of an Axially Compressed Weakened Element with a Symmetric Weakening Reaching the Edge
Objective: Check of the calculation of the resistance of sections.
Task: Verify the correctness of the stability analysis of normal sections.
References: Nasonov S.B. Manual on design and analysis of building structures. – M: ASV Publishing House, 2013. – p. 67-68.
Initial data file:
Example 5.SAV;
report – Decor 5.doc.
Software version: DECOR 21.1.1.1, 17.02.2016.
Compliance with the codes: SNiP ІІ-25-80, SP 64.13330.2011.
Initial data from the source:
| b×h = 15×20 cm | Section sizes of the element |
| а = 20 mm | Height of the weakened section (Fig. 1) |
| l = 4 m | Member length |
| μx = μy = 1 | Effective length factors |
| N = 100 kN | Compressive force |
| Material of the element: pine. | |
| Grade of wood: 2. | |
| Operating conditions class: 1 (А2 according to SNiP ІІ-25-80). | |
DECOR initial data:
Importance factor γn = 1
|
Service factors |
|
|
Service factor for temperature and humidity operating conditions mВ |
1 |
|
Allowance for the temperature conditions of operation mТ |
1 |
|
Allowance for the duration of loading md |
1 |
|
Service factor under short-term loads mn |
1 |
|
Factor that allows for the effect of impregnation with protective substances mа |
1 |
Wood species - Pine
Grade of wood - 2
Limit slenderness of members in tension - 200
Limit slenderness of members in compression - 120
Member length 4 m
Effective length factor in the XoY plane - 1
Effective length factor in the XoZ plane - 1
Section:
|
b = 150 mm Non-glued timber section
|
|
Weakening reaching the edge
Area of the weakening - 60 cm2
Forces:
N = -100 kN
My = 0 kN*m
Qz = 0 kN
Mz = 0 kN*m
Qy = 0 kN
Comparison of solutions:
|
File |
Example 5.SAV |
|
Report file |
Decor 5.doc |
|
Check |
Stability in the XOY plane under a longitudinal force |
|
Theory |
1,19/1,5 = 0,793 |
|
DECOR |
0,79 |
|
Deviation, % |
0,4 % |
Comments:
- The area of the weakening in the section is determined as 2(а×b) = 2 ∙ (2×15) = 60 cm2.
- Service factor for 1 (А2) class mв = 1 (table 5 of SNiP ІІ-25-80, table 7 of SP 64.13330.2011).
- Limit slenderness of the compressed element is equal to λmax = 120 (table 14 of SNiP ІІ-25-80, table 17 of SP 64.13330.2011).