Check of the Load-bearing Capacity of a Section of an Axially Compressed Element Weakened by Holes in a Section of 150 mm
Objective: Check of the calculation of the resistance of sections.
Task: Verify the correctness of the stability analysis of normal sections.
References: Nasonov S.B. Manual on design and analysis of building structures. – M: ASV Publishing House, 2013. – p. 68-69.
Initial data file:
Example 6.SAV;
report – Decor 6.doc.
Software version: DECOR 21.1.1.1, 28.03.2016.
Compliance with the codes: SNiP ІІ-25-80, SP 64.13330.2011.
Initial data from the source:
| b×h = 20×15 cm | Section sizes of the element |
| d = 40 mm | Diameter of the hole |
| а = 150 mm | Distance between the centers of the holes |
| l = 3 m | Member length |
| μx = μy = 1 | Effective length factors |
| N = 100 kN | Compressive force |
| Material of the element: pine. | |
| Grade of wood: 2. | |
| Operating conditions class: 1 (А2 according to SNiP ІІ-25-80). | |
DECOR initial data:
Importance factor γn = 1
|
Service factors |
|
|
Service factor for temperature and humidity operating conditions mВ |
1 |
|
Allowance for the temperature conditions of operation mТ |
1 |
|
Allowance for the duration of loading md |
1 |
|
Service factor under short-term loads mn |
1 |
|
Factor that allows for the effect of impregnation with protective substances mа |
1 |
Wood species - Pine
Grade of wood - 2
Limit slenderness of members in tension - 200
Limit slenderness of members in compression - 120
Member length 3 m
Effective length factor in the XoY plane - 1
Effective length factor in the XoZ plane – 1
Section:
|
b = 200 mm Non-glued timber section
|
|
|---|
Weakening not reaching the edge
Area of the weakening - 80 cm2
Forces:
N = -100 kN
My = 0 kN*m
Qz = 0 kN
Mz = 0 kN*m
Qy = 0 kN
Comparison of solutions:
|
File |
Example 6.SAV |
|
Report file |
Décor 6.doc |
|
Check |
Stability in the XOZ plane under a longitudinal force |
|
Theory |
0,55/1,5 = 0,367 |
|
DECOR |
0,369 |
|
Deviation, % |
0,62 % |
Comments:
- The area of the weakening in the section is determined as the product of the width of the cross-section by the diameter of the hole 20×4 = 80 cm2.
- Service factor for 1 (А2) class mв = 1 (table 5 of SNiP ІІ-25-80, table 7 of SP 64.13330.2011).
- Limit slenderness of the compressed element is equal to λmax = 120 (table 14 of SNiP ІІ-25-80, table 17 of SP 64.13330.2011).